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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Along a road lies an odd number of stones placed at intervals of 10 m10 \mathrm{~m}. These stones have to be assembled around the middle stone. A person can carry only one stone at a time. A man carried out the job starting with the stone in the middle, carrying stones in succession, thereby covering a distance of 4.8 km4.8 \mathrm{~km}. Then, the number of stones is
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Correct option: C
31
Option C (31) is correct because the total distance covered is 20n(n+1)20n(n+1) meters, where nn is the number of stones on each side of the middle stone, and solving for nn gives n=15n=15, so the total number of stones is 2n+1=312n+1 = 31.

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