JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The value of

1 - {\log _e}2 + \frac{{{{\left( {{{\log }_e}2} \right)}^2}}}{{2\;!}} - \frac{{{{\left( {{{\log }_e}2} \right)}^3}}}{{3\;!}} + \ldots ,

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Correct option: B

\frac{1}{2}

Option B is correct because the given expression is the Taylor series expansion of e^(-log(2)), which simplifies to 1/2.

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