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JEE MATHEMATICS MCQ: PERMUTATIONS

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Application +4 | -1
The total number of ways of selecting two numbers from the set {1,2,3,4,…,3n}\{1,2,3,4, \ldots, 3 n\}, so that their sum of divisible by 3, is
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Correct option: B
3n2−n2\frac{3 n^2-n}{2}
Option B (3n2−n2\frac{{3 n^2-n}}{{2}}) is correct because it accounts for selecting two numbers from the same remainder group modulo 3 or one number from each of the two different remainder groups.

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