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NEET UG CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

1 Easy
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Application +4 | -1
Oxidation state of oxygen in compounds OF2\mathrm{OF}_2 and Na2O\mathrm{Na}_2 \mathrm{O} respectively are
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Correct option: A
+2,−2+2,-2
Option A (+2, -2) is correct because in OF2, oxygen is bonded to the more electronegative fluorine, giving it a positive oxidation state, while in Na2O, oxygen is bonded to the less electronegative sodium, giving it a negative oxidation state.

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