A sample of HCl gas is placed in an electric field of $3 \times {10^4}{\rm{\;N}}{{\rm{C}}^{ - 1}}$. The dipole moment of each HCl molecule is $6 \times {10^{ - 30}}$ $Cm$ The maximum torque that can act on a molecule is

$2 \times {10^{ - 34}}{{\rm{C}}^2}{\rm{m}}{{\rm{N}}^{ - 1}}$

$0.5 \times {10^{34}}{{\rm{C}}^{ - 2}}{\rm{N}}{{\rm{m}}^{ - 1}}$

JEE PHYSICS MCQ: ELECTRIC POTENTIAL AND CAPACITANCE

1 Medium

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Application +4 | -1

A sample of HCl gas is placed in an electric field of

3 \times {10^4}\mathrm{\;N}{\mathrm{C}^{ - 1}}

. The dipole moment of each HCl molecule is

6 \times {10^{ - 30}}

Cm

The maximum torque that can act on a molecule is

View answer and explanation

Correct option: C

18 \times {10^{ - 26}}

The correct answer is C (

18 \times {10^{ - 26}}

Nm) because the maximum torque on a dipole in an electric field is given by

\tau = pE

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x

\mu \mathrm{m}

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3\mu F,\,

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E

E