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JEE MATHEMATICS MCQ: PERMUTATIONS

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The number of ways in which the letters of the word 'SUCCESSFUL' be arranged such that no two S's will come together is

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Correct option: D

\frac{7 !}{2 ! 2 !} \frac{{ }^8 P_3}{3 !}

The correct answer is D (

\frac{7 !}{2 ! 2 !} \frac{{ }^8 P_3}{3 !}

) because it accounts for arranging the non-S letters and then placing the S's in the gaps.

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