JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

Let

f(x) = x + \sin x,

suppose

g

denotes the inverse function of

f.

Then, find the value of

g'\left( {\frac{\pi }{4} + \frac{1}{{\sqrt 2 }}} \right)

View answer and explanation

Correct option: C

2 - \sqrt 2

Option C (

2 - \sqrt 2

) is correct because it is the value of the derivative of the inverse function g at the given point, calculated using the derivative of f.

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