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JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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Application +4 | -1
The motion of a particle along a straight line is described by equation x=2+12t−t2x=2+12 t-t^2, where xx is in metre and tt is in second. The retardation of the particle when its velocity becomes zero is
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Correct option: A
2 m/s22 \mathrm{~m} / \mathrm{s}^2
Option A (2 m/s22 \mathrm{~m} / \mathrm{s}^2) is correct because the retardation is the magnitude of the acceleration when the velocity is zero.

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