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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
If ∫−2−1(ax2−5)dx=0\int_{-2}^{-1}\left(a x^2-5\right) d x=0 and 5+∫12(bx+c)dx=05+\int_1^2(b x+c) d x=0, then
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Correct option: B
ax2−bx+c=0a x^2-b x+c=0 has atleast one root in (−2,−1)(-2,-1)
Option A (g(x)g(x) must be differentiable at x=ax=a) is correct because for f(g(x))f(g(x)) to be differentiable at x=ax=a, g(x)g(x) must also be differentiable at x=ax=a.

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