JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1

Let

\,\,F(x)=f(x)+f\left(\frac{1}{x}\right)

where

f(x)=\int\limits_{1}^x \frac{\log _e t}{1+t} d t

Then

F(e)

is equal to

View answer and explanation

Correct option: C

\frac{1}{2}

The correct answer is C (

\frac{1}{2}

) because after applying Leibnitz rule and integration, F(e) is found to be

\frac{1}{2}

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