JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Analyzing +4 | -1

A curve with equation of the form

y=a x^4+b x^3+c+c x+d

has zero gradient at the point

(0,1)

and also touches the

x

-axis at the point

(-1,0)

then the values of the

x

for which the curve has a negative gradient are:

View answer and explanation

Correct option: C

x < -1

Option C (

x < -1

) is correct because it identifies the range of x-values where the derivative of the curve is negative, indicating a negative gradient.

More Questions from TANGENTS & NORMALS

Practice All Chapter MCQs →

a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z