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JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

A spring produces extension '

x

' by applying a force '

F

' N. A body of mass '

m

' suspended from spring oscillates vertically with a period '

T

', the mass of the suspended body is (neglect mass of spring)

View answer and explanation

Correct option: A

\frac{T^2 F}{4 \pi^2 x}

Option A (

\frac{T^2 F}{4 \pi^2 x}

) is correct because it correctly relates the mass of the suspended body to the spring constant, time period, and extension.

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