$\mathop {\lim }\limits_{x \to \infty } \frac{{4{x^5} + 9x + 7}}{{3{x^5} + {x^4} + {x^2} + 1}} = $

JEE MATHEMATICS MCQ: LIMITS

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\lim\limits_{x \to \infty } \frac{{4{x^5} + 9x + 7}}{{3{x^5} + {x^4} + {x^2} + 1}} =

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Correct option: C

\frac{4}{3}

Option C (4/3) is correct because as x approaches infinity, the highest power terms dominate, and the limit is the ratio of their coefficients.

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