Identify $A$ and $B$ in the reaction given below. ${\rm{Ethane nitrile}}\,\,\mathop {{\rm{\;}}\mathop \to \limits^{{\rm{\;Hydrolysis}}} }\limits_{\begin{array}{*{20}{c}} {aq.{{\rm{H}}_2}S{{\rm{O}}_4}}\\ { + 2{{\rm{H}}_2}O}\\ { - N{{\rm{H}}_3}} \end{array}} \;A\;\mathop {\mathop \to \limits^{{\rm{Decarboxylation}}} }\limits_{\begin{array}{*{20}{c}} {Sodalime}\\ \Delta \\ { - C{{\rm{O}}_2}} \end{array}} {\rm{\;}}B$

NEET UG CHEMISTRY MCQ: AMINES

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Application +4 | -1

Identify

A

and

B

in the reaction given below.

\mathrm{Ethane nitrile}\,\,\mathop {\mathrm{\;}\mathop \to \limits^{\mathrm{\;Hydrolysis}} }\limits_{\begin{array}{cccccccccccccccccccc} {aq.{\mathrm{H}_2}S{\mathrm{O}_4}}\\ { + 2{\mathrm{H}_2}O}\\ { - N{\mathrm{H}_3}} \end{array}} \;A\;\mathop {\mathop \to \limits^{\mathrm{Decarboxylation}} }\limits_{\begin{array}{cccccccccccccccccccc} {Sodalime}\\ \Delta \\ { - C{\mathrm{O}_2}} \end{array}} \mathrm{\;}B

View answer and explanation

Correct option: D

Ethanoic acid, methane

Option D (Ethanoic acid, methane) is correct because hydrolysis of ethane nitrile yields ethanoic acid, and decarboxylation of ethanoic acid with sodalime yields methane.

NEET UG CHEMISTRY MCQ: AMINES

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