JEE MATHEMATICS MCQ: LIMITS

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Application +4 | -1

Let

\alpha=\lim \limits_{{n \rightarrow \infty}} \frac{\left(1^3-1^2\right)+\left(2^3-2^2\right)+\ldots+\left(n^3-n^2\right)}{n^4}

, then

\alpha

is equal to:

View answer and explanation

Correct option: B

\frac{1}{4}

Option B (1/4) is correct because the limit of the given expression as n approaches infinity simplifies to 1/4 after evaluating the sums.

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