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JEE PHYSICS MCQ: NUCLEI

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Application +4 | -1
The radius RR of a nucleus of mass number AA can be estimated by the formula R=(1.3×10−15)A1/3m.R = (1.3 \times \mathrm{1}{\mathrm{0}^{ - 15}}){A^{1/3}}m. It follows that the mass density of a nucleus is of the order of (Mproton≅Mneutron≃1.67×10−27  kg)({M_{proton}} \cong {M_{neutron}} \simeq 1.67 \times {10^{ - 27}}\mathrm{\,\,kg)}
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Correct option: A
1017  kg m−3{10^{17}}\mathrm{\,\,kg}\,{\mathrm{m}^{ - 3}}
Option A (1017 kg m−3{10^{17}}\mathrm{\ kg}\,{\mathrm{m}^{ - 3}}) is correct because it is the approximate mass density of a nucleus, independent of the mass number A.

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