JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

Let

a_n

be the

n

th term of an AP, if

\sum\limits_{r = 1}^{100} {{a_{2r}}} = \alpha \,\,{\text{and}}\,\,\,\sum\limits_{r = 1}^{100} {{a_{2r - 1}}} = \beta ,

then the common difference of the AP is

View answer and explanation

Correct option: C

\frac{\alpha-\beta}{100}

Option C (

\frac{\alpha-\beta}{100}

) is correct because it represents the common difference of the AP, derived from the given sums of even and odd terms.

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