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JEE CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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R−OH→PCl3A→dry etherNaH3C−C∣HCH3∣−C∣HCH3∣−CH3R - OH\xrightarrow{{PC{l_3}}}{\text{A}}\xrightarrow[{{\text{dry ether}}}]{{Na}}{H_3}C - \mathop C\limits_{\begin{array}{cccccccccccccccccccc} | \\ H \end{array}}^{\begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \end{array}} - \mathop C\limits_{\begin{array}{cccccccccccccccccccc} | \\ H \end{array}}^{\begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \end{array}} - C{H_3}
The value of R in above reaction is
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Correct option: B
CH3−C∣HCH3∣−C{H_3} - \mathop C\limits_{\begin{array}{cccccccccccccccccccc} | \\ H \end{array}}^{\begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \end{array}} -
The correct answer is B (CH3−C∣HCH3∣−C{H_3} - \mathop C\limits_{\begin{array}{cccccccccccccccccccc}| \\ H \end{array}}^{\begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \end{array}} -) because the given product is formed via a Wurtz reaction, requiring two identical alkyl halides derived from the same alcohol.

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