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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
If ∫  x  tan⁡−1x1+x2  dx=  1+x2  f(x)  +  A  log⁡  (x+x2+1)+C\int \,\,\frac{{x\,\,{{\tan }^{ - 1}}x}}{{\sqrt {1 + {x^2}} }}\,\,dx = \,\,\sqrt {1 + {x^2}} \,\,f\left( x \right)\,\, + \,\,A\,\,\log \,\,\left( {x + \sqrt {{x^2} + 1} } \right) + C, then
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Correct option: C
f  (x)=2  tan⁡−1  x,  A=−1f\,\,\left( x \right) = 2\,\,{\tan ^{ - 1}}\,\,x,\,\,A = - 1
Option A is correct because after integrating by parts and simplifying, the resulting function f(x) and constant A match the values given in option A.

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