JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

Let

\alpha ,{\alpha ^2}

be the roots of

{x^2} + x + 1 = 0

, then the equation whose roots are

{\alpha ^{31}},\;{\alpha ^{62}}

View answer and explanation

Correct option: C

{x^2} + x + 1 = 0

Option C (

{x^2} + x + 1 = 0

) is correct because the new roots

{\alpha ^{31}}

and

{\alpha ^{62}}

satisfy the same quadratic equation as

\alpha

and

{\alpha ^2}

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