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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
If f(n)=∏i=2n−1log⁡i(i+1),f\left( n \right) = \prod\limits_{i = 2}^{n - 1} {{{\log }_i}\left( {i + 1} \right),} the value of ∑k=1100f(2k)\sum\limits_{k = 1}^{100} {f\left( {{2^k}} \right)} equals
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Correct option: B
5050
Option B (5050) is correct because the product simplifies to a logarithm, and the sum of the first 100 integers is 5050.

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