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JEE PHYSICS MCQ: OSCILLATIONS

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Analyzing +4 | -1
A student says that he had applied a force F=−kxF=-k \sqrt{x} on a particle and the particle moved in simple harmonic motion. He refuses to tell whether k{k} is constant or not. Assume that he has worked only with positive x{x} and no other force acted on the particle
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Correct option: A
as x{x} increases k{k} increases
Option A (as x{x} increases k{k} increases) is correct because for SHM, the force is proportional to x, and comparing with the given force, k must increase with x.

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