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JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1
If the tangent at any point PP on the ellipse x2a2+y2b2=1\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1 meets the tangents at the vertices AA and A′A' in LL and L′L' respectively, then AL.A′L′=AL.A'L' =
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Correct option: D
b2{b^2}
Option D (b2{b^2}) is correct because the product of the lengths AL and A'L' is equal to b2, a property of the ellipse.

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