An electrical cable having a resistance of $0.2\,\,{\rm{\Omega }}$ delivers $10\,\,{\rm{k}}\,{\rm{W}}$ at $200\,\,V\,{\rm{D}}\,{\rm{C}}$ to a factory. What is the efficiency of transmission

$\begin{array}{*{20}{l}} {{\rm{95}}\,\,{\rm{\% }}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{65}}\,\,{\rm{\% }}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{75}}\,\,{\rm{\% }}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{85}}\,\,{\rm{\% }}} \end{array}$

JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Application +4 | -1

An electrical cable having a resistance of

0.2\,\,\mathrm{\Omega }

delivers

10\,\,\mathrm{k}\,\mathrm{W}

200\,\,V\,\mathrm{D}\,\mathrm{C}

to a factory. What is the efficiency of transmission

View answer and explanation

Correct option: D

\begin{array}{llllllllllllllllllll} {\mathrm{95}\,\,\mathrm{\% }} \end{array}

Option D (

\begin{array}{llllllllllllllllllll}{\mathrm{95}\,\,\mathrm{\% }}\end{array}

) is correct because it represents the efficiency of transmission calculated by accounting for power loss in the cable.