The perfect gas goes from a state A to another state B by absorbing $8 \times {10^5}$J of heat and doing $6.5 \times {10^5}{\rm{J}}$of external work. It is now transferred between the same two states in another process in which it absorbs ${10^5}J$ of heat in the second process. Then

Work done on the gas is $0.5 \times {10^5}{\rm{J}}$

Work done on the gas is ${10^5}J$

NEET UG PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

The perfect gas goes from a state A to another state B by absorbing

8 \times {10^5}

J of heat and doing

6.5 \times {10^5}\mathrm{J}

of external work. It is now transferred between the same two states in another process in which it absorbs

{10^5}J

of heat in the second process. Then

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Correct option: A

Work done on the gas is

0.5 \times {10^5}\mathrm{J}

Work done on the gas is

0.5 \times {10^5}\mathrm{J}

because the change in internal energy is path-independent, and the difference in heat absorbed corresponds to the difference in work done.