JEE PHYSICS MCQ: ATOMS

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Analyzing +4 | -1

A beam of monochromatic light of wavelength

\lambda

ejects
photoelectrons from a cesium surface

(\phi = 1.9 \text{ eV}).

These
photoelectrons are made to collide with hydrogen atoms
in ground state. Find the maximum value of

\lambda

for which

(a) hydrogen atoms may be ionized,
(b) hydrogen atoms
may get excited from the ground state to the first excited
state

View answer and explanation

Correct option: A

(a)

80 \mathrm{~nm};

(b)

102 \mathrm{~nm};

Option A ((a)

80 \mathrm{~nm};

(b)

102 \mathrm{~nm};

) is correct because it accurately calculates the maximum wavelengths for hydrogen ionization and excitation using the photoelectric effect and energy level transitions.

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The de-Broglie wavelength of an electron in the first Bohr orbit is The volume occupied by an atom is greater than the volume of the nucleus by a factor of about For a hydrogen atom, when electron jump from

n

=2

{n}=1

, then wave length of radiation emitted found to be

\lambda_0

. Then, for which transition of electron of a 'He' atom, the wavelength of radiation emitted will be equal to '

\lambda_0

'. Energy of characteristic X-ray is a consequence of Taking Rydberg’s constant

{R_H} = 1.097\,\, \times \,\,{10^7}\,\,m

, first and second wavelength of Balmer series in hydrogen spectrum is When hydrogen atom is in its first excited level, its radius is its ground state radius