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JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

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If tan⁡3Atan⁡A=k\frac{\tan ^3 A}{\tan A}=k, then sin⁡3Asin⁡A\frac{\sin 3 A}{\sin A} is equal to
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Correct option: A
2kk−1\frac{2 k}{k-1}
Option A (2kk−1\frac{2 k}{k-1}) is correct because by using trigonometric identities and simplifying the given expression, we can find that sin⁡3Asin⁡A=2kk−1\frac{\sin 3 A}{\sin A} = \frac{2k}{k-1}.

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