JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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The radius of which of the following orbit is same as that of first Bohr’s orbit of Hydrogen atom

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Correct option: D

B{e^{ + 3}}\left( {n = 2} \right)

Option D (

Be^{+3}(n=2)

) is correct because the radius of its second orbit is the same as the first Bohr's orbit of Hydrogen atom, calculated using the formula r = 0.529 * (n²/Z).

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