If $x = \sin t,y = \cos pt,$, then

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

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Application +4 | -1

x = \sin t,y = \cos pt,

, then

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Correct option: D

\left( {1 - {x^2}} \right){y_2} - x{y_1} + {p^2}y = 0

Option D (

\left( {1 - {x^2}} \right){y_2} - x{y_1} + {p^2}y = 0

\) is correct because it is the differential equation obtained after differentiating the given parametric equations and eliminating the parameter

t

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