NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

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The potential energy of a particle in a force field is

U = \frac{A}{{{r^2}}} - \frac{B}{r}

, where A and B are positive constants and r is the distance of particle from the centre of the field. For stable equilibrium, the distance of the particle is

View answer and explanation

Correct option: B

2A/B

Option B (2A/B) is correct because it is found by setting the derivative of the potential energy function to zero and solving for r.

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