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JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1
Suppose that g(x)=1+xg(x)=1+\sqrt{x} and f(g(x))=3+2x+xf(g(x))=3+2 \sqrt{x}+x, then f(x)f(x) is
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Correct option: B
2+x22+x^2
Option B (2+x22+x^2) is correct because substituting g(x)g(x) into f(g(x))f(g(x)) and solving for f(x)f(x) yields 2+x22+x^2.

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