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JEE CHEMISTRY MCQ: SOLUTIONS

1 Hard
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Understanding +4 | -1
Assertion (A) : Water in a beaker cannot be made to boil by placing it in a bath of boiling water.

Reason (R) : Water in the beaker will be heated to 100∘C100^{\circ} \mathrm{C} but will not boil as for boiling it requires latent heat of steam which is not provided by water bath as both attains 100∘C100^{\circ} \mathrm{C}.
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Correct option: C
Both Assertion and Reason are correct and Reason is correct explantion of Assertion
Option C is correct because water in a beaker cannot boil in a boiling water bath as it needs latent heat, which the water bath cannot provide once both reach 100°C.

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An aqueous solution of a solute which neither associates nor dissociates has a freezing point depression of X∘C.\mathrm{X}^{\circ} \mathrm{C}. An equimolal solution of a second salt has a freezing point depression of 3X∘C.3 \mathrm{X}^{\circ} \mathrm{C}. Assuming 100%100 \% dissociation of salt, the second solution could be a salt of formula Read the following statements carefully and choose the correct option

(i) Osmotic pressure is not a colligative property.

(ii) For dilute solutions, osmotic pressure is proportional to the molarity, C{C} of the solution at a given temperature TT.

(iii) During osmosis, solvent molecules always flow from higher concentration to lower concentration of solution.

(iv) The osmotic pressure has been found to depend on the concentration of the solution
A solution that obeys Raoult’s law is called When two liquids AA and BB are mixed they form an ideal solution. At certain temperature the V.P. of the solution, that contains 3 moles of AA and 1 mole of BB was found to be 550 mm550 \mathrm{~mm} of Hg\mathrm{Hg}. The vapour pressure of a solution containing 4 moles of AA and 1 mole of BB was found to be 560 mm\mathrm{mm} of Hg\mathrm{Hg}. The vapour pressure of pure liquid AA is Equal masses of two aqueous solutions, one of 3.6 g3.6 \, \mathrm{g} glucose per 100 g100 \mathrm{~g} of water and the other of 3.6 g3.6 \mathrm{~g} urea per 100 g100 \mathrm{~g} of water are mixed. If the freezing point of resulting solution is −x∘C,-x^{\circ} \mathrm{C}, then the value of '1000x1000 x' is (Kf\left(K_{\mathrm{f}}\right. of water =1.86)\left.=1.86\right) Information

I. Semipermeable membrane contains network of submacroscopic holes or pores.

II. Semipermeable membrane appears to be continuous sheets or films.

III. Solvent molecules cannot pass through the holes of semipermeable membrane but solute molecules can pass On the basis of the information given above select the correct option.
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