If $n(A)=n(B)=4$ then number of bijections from $A$ to $B$ is

JEE MATHEMATICS MCQ: BINOMIAL THEOREM

1 Easy

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Understanding +4 | -1

n(A)=n(B)=4

then number of bijections from

A

B

View answer and explanation

Correct option: B

Option A (

\frac{1}{2}(n+1)(n+2)

) is correct because the number of terms in the expansion of

(x+y+z)^n

is equivalent to the number of non-negative integer solutions to the equation

p+q+r=n

, which is given by

{n+3-1 \choose 3-1} = {n+2 \choose 2} = \frac{(n+2)(n+1)}{2}

Practice All Chapter MCQs →

\left({ }^{10} C_0\right)^2-\left({ }^{10} C_1\right)^2+\ldots-\left({ }^{10} C_9\right)^2+\left({ }^{10} C_{10}\right)^2

a

d

\left( {n + 1} \right)

a{C_0} - \left( {a + d} \right){C_1} + \left( {a + 2d} \right){C_2} - ... + ...

(1-x)^{201}\left(1+x+x^2\right)^{200}

\left(\frac{1}{x}+2 x\right)^n

{x^5}

\frac{{1 + {x^2}}}{{1 + x}},\left| x \right| < 1,

\left(\begin{array}{c}2 n+1 \\ 0\end{array}\right)+\left(\begin{array}{c}2 n+1 \\ 3\end{array}\right)+\left(\begin{array}{c}2 n+1 \\ 6\end{array}\right)+\ldots=170

n