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JEE PHYSICS MCQ: RAY OPTICS

1 Medium

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Understanding +4 | -1

The condition for an achromatic doublet, is (

{f_1}\,\,{\text{and }}{f_2}

are the focal lengths of individual lenses)

View answer and explanation

Correct option: C

\frac{{{\omega _1}}}{{{f_1}}} + \frac{{{\omega _2}}}{{{f_2}}} = 0

Option C is correct because the condition for an achromatic doublet is given by

\frac{{\omega_1}}{{f_1}} + \frac{{\omega_2}}{{f_2}} = 0

, where

\omega

represents dispersive power and f represents focal length.

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