When a helium nucleus covers a circle of radius $0.8 \mathrm{~m}$ in $2 \mathrm{~s}$, find the value of magnetic field $B$ at the centre of the circle.

$\frac{10^{-19}}{\mu_0} \mathrm{~T}$

$2 \mu_0 \times 10^{-19} \mathrm{~T}$

$\frac{2 \times 10^{-19}}{\mu_0} \mathrm{~T}$

NEET UG PHYSICS MCQ: MAGNETIC EFFECT OF CURRENT

1 Hard

1 of 1

Application +4 | -1

When a helium nucleus covers a circle of radius

0.8 \mathrm{~m}

2 \mathrm{~s}

, find the value of magnetic field

B

at the centre of the circle.

View answer and explanation

Correct option: B

\mu_0 \times 10^{-19} \mathrm{~T}

Option B (

\mu_0 \times 10^{-19} \mathrm{~T}

) is correct because it is the magnetic field calculated at the center of the circle using the given radius, time, and charge of the helium nucleus.

Practice All Chapter MCQs →

5 \mathrm{~cm}

12 \mathrm{~cm}

250 \mu \mathrm{T}

d \vec{B}

d \vec{l}

\vec{r}

i

\oint {\overrightarrow B .\overrightarrow {dl} }