Consider the ions ${{\rm{K}}^ + },{\rm{\;}}{{\rm{S}}^{2 - }},{\rm{C}}{{\rm{l}}^ - }{\rm{\;and\;C}}{{\rm{a}}^{2 + }}$. The radii of these ionic species follow the order

${{\rm{S}}^{2 - }} > C{{\rm{l}}^ - } > {{\rm{K}}^ + } > {\rm{C}}{{\rm{a}}^{2 + }}{\rm{\;}}$

${\rm{C}}{{\rm{a}}^{2 + }} > {{\rm{K}}^ + } > C{{\rm{l}}^ - } > {{\rm{S}}^{2 - }}$

${\rm{C}}{{\rm{l}}^ - } > {{\rm{S}}^{2 - }} > {{\rm{K}}^ + } > {\rm{C}}{{\rm{a}}^{2 + }}$

${\rm{C}}{{\rm{a}}^{2 + }} > C{{\rm{l}}^ - } > K > {{\rm{S}}^{2 - }}$

NEET UG CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

1 Easy

1 of 1

Understanding +4 | -1

Consider the ions

{\mathrm{K}^ + },\mathrm{\;}{\mathrm{S}^{2 - }},\mathrm{C}{\mathrm{l}^ - }\mathrm{\;and\;C}{\mathrm{a}^{2 + }}

. The radii of these ionic species follow the order

View answer and explanation

Correct option: D

{\mathrm{S}^{2 - }} > C{\mathrm{l}^ - } > {\mathrm{K}^ + } > \mathrm{C}{\mathrm{a}^{2 + }}\mathrm{\;}

Option D (

{\mathrm{S}^{2 - }} > C{\mathrm{l}^ - } > {\mathrm{K}^ + } > {\mathrm{Ca}^{2 + }}\mathrm{\;}

) is correct because ionic radii decrease with increasing nuclear charge and increase with increasing negative charge.