A screw gauge has least count of ${\rm{0}}{\rm{.01 mm}}$ and there are ${\rm{50}}$ divisions in its circular scale. The pitch of the screw gauge is :

${\rm{0}}{\rm{.5}}\,\,{\rm{mm}}$

${\rm{0}}{\rm{.01}}\,\,{\rm{mm}}$

${\rm{0}}{\rm{.25}}\,\,{\rm{mm}}$

${\rm{1}}{\rm{.0}}\,\,{\rm{mm}}$

NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

1 Medium

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Application +4 | -1

A screw gauge has least count of

\mathrm{0}\mathrm{.01 mm}

and there are

\mathrm{50}

divisions in its circular scale. The pitch of the screw gauge is :

View answer and explanation

Correct option: C

\mathrm{0}\mathrm{.5}\,\,\mathrm{mm}

Option C (

\mathrm{0}\mathrm{.5}\,\mathrm{mm}

) is correct because the pitch is calculated by multiplying the least count by the number of divisions on the circular scale.