JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Analyzing +4 | -1

n \tan y=\tan x, n \in R^{+}

, then the maximum value of

\sec ^2(x-y)

is equal to

View answer and explanation

Correct option: D

\frac{(n+1)^2}{4 n}

Option A (

n \pi-\frac{{\pi}}{{4}}

) is correct because it represents the general solution where the real part of the given complex expression is zero, making it purely imaginary.

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