The product formed in the reaction of H$X$ with ${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{C}}$=${\rm{C}}{{\rm{H}}_2}$ is:

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{C}}X{\rm{C}}{{\rm{H}}_3}$

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{CH}} \cdot {\rm{C}}{{\rm{H}}_2}X$

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{CHC}}{{\rm{H}}_3}$

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{C}}X{\rm{C}}{{\rm{H}}_2}X$

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NEET UG CHEMISTRY MCQ: HALOALKANES AND HALO ARENES

1 Easy

1 of 1

Application +4 | -1

The product formed in the reaction of H

X

with

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{C}

\mathrm{C}{\mathrm{H}_2}

is:

View answer and explanation

Correct option: A

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{C}X\mathrm{C}{\mathrm{H}_3}

Option A (

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{C}X\mathrm{C}{\mathrm{H}_3}

) is correct because the addition of HX to an alkene follows Markovnikov's rule, where the hydrogen adds to the carbon with more hydrogens, and the halogen adds to the more substituted carbon.

NEET UG CHEMISTRY MCQ: HALOALKANES AND HALO ARENES

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