NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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Analyzing +4 | -1

Two electrochemical cells are assembled in which the following reactions occur:

\begin{aligned} & \mathrm{V}^{2+}+\mathrm{VO}^{2+}+2 \mathrm{H}^{+} \rightarrow 2 \mathrm{V}^{3+}+\mathrm{H}_2 \mathrm{O} ; E^{\circ}_{\text {Cell }}= 0.616 \mathrm{~V} \\ & \mathrm{V}^{3+}+\mathrm{Ag}^{+}+\mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{VO}^{2+}+\mathrm{Ag}(\mathrm{s})+2 \mathrm{H}^{+} ; E^{\circ}_\text {Cell} =0.439 \mathrm{~V} \end{aligned}

E_{\mathrm{Ag}^{+} \mid \mathrm{Ag}^{\circ}}^{\circ}=0.799 \mathrm{~V}

, what is

E_{\mathrm{V}^{3+} \mid \mathrm{V}^{2+}}^{\circ}?

View answer and explanation

Correct option: A

-0.256 \mathrm{~V}

Option A (

-0.256 \mathrm{~V}

) is correct because it is calculated by manipulating the given cell potentials and the standard reduction potential of Ag+/Ag to find the standard reduction potential of V3+/V2+.

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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