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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy
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Application +4 | -1
If cos⁡−1x+cos⁡−1(y/2)=α\cos ^{-1} x+\cos ^{-1}(y / 2)=\alpha, then 4x2−4xycos⁡α+y24 x^2-4 x y \cos \alpha+y^2 is equal to
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Correct option: A
4sin⁡2α4 \sin ^2 \alpha
Option A (4sin⁡2α4 \sin ^2 \alpha) is correct because by applying the cosine subtraction formula and simplifying, the expression 4x2−4xycos⁡α+y24 x^2-4 x y \cos \alpha+y^2 is equal to 4sin⁡2α4 \sin ^2 \alpha.

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