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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
If for a continuous function f(x),∫−πt(f(x)+x)dx=π2−f(x), \int\limits_{{-\pi}}^t(f(x)+x) d x=\pi^2- t2t^2, for all t≥−πt \geq-\pi, then f(−π3)f\left(-\frac{\pi}{3}\right) is equal to:
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Correct option: A
π\pi
Option A (π\pi) is correct because after differentiating the given integral equation and solving for f(x), we find f(-π3\frac{\pi}{3}) = π\pi.

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