JEE MATHEMATICS MCQ: ELLIPSE

1 Easy

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Application +4 | -1

The locus of pole of tangents to the ellipse

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

with respect to the parabola

y^2=4 a x

, is

View answer and explanation

Correct option: C

b^2 y^2=4 a^2\left(x^2-a^2\right)

Option C (

b^2 y^2 = 4 a^2 (x^2 - a^2)

) is correct because the locus of the pole is found by equating the polar equation to the tangent equation and using the condition for tangency.

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