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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
∫−π/2π/2sin⁡4xcos⁡6xdx=\int\limits_{{-\pi / 2}}^{\pi / 2} \sin ^4 x \cos ^6 x d x=
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Correct option: C
3π256\frac{3 \pi}{256}
Option C (3π/256) is correct because the integral of sin4(x)cos6(x) from -π/2 to π/2 evaluates to 3π/256 using the Gamma function.

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