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JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy
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Application +4 | -1
Find the remainder when 1!+2!+3!+…+n1 !+2 !+3 !+\ldots+n! is divided by 15, if n≥5n \geq 5.
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Correct option: C
3
Option C (3) is correct because for n ≥ 5, all terms from 5! onwards are divisible by 15, so the remainder is determined by the sum of the first four terms.

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