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JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1
Let f(x)=log⁡e(x2+ex)log⁡e(x4+e2x)f(x)=\frac{\log _e\left(x^2+e^x\right)}{\log _e\left(x^4+e^{2 x}\right)}. If lim⁡x→∞f(x)=l\lim \limits_{{x \rightarrow \infty}} f(x)=l and lim⁡x→−∞f(x)=m\lim \limits_{{x \rightarrow-\infty}} f(x)=m, then
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Correct option: A
l=ml=m
Option B (pq\sqrt{pq}) is correct because it is obtained by converting the limit to an exponential form and using L'Hopital's rule or the properties of limits.

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