JEE MATHEMATICS MCQ: ELLIPSE

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Understanding +4 | -1

The equation

x=a \cos \theta, y=b \sin \theta(a>b)

represents a conic section whose eccentricity

e

is given by

View answer and explanation

Correct option: C

e^2=\frac{a^2-b^2}{a^2}

Option C (

e^2=\frac{a^2-b^2}{a^2}

) is correct because the equation represents an ellipse, and the eccentricity of an ellipse is given by

e = \sqrt{1 - \frac{b^2}{a^2}}

, so

e^2 = \frac{a^2 - b^2}{a^2}

More Questions from ELLIPSE

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\frac{x^2}{144}+\frac{y^2}{81}=1

m

\mathrm{M}

\mathrm{mM}

P

\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1

S

S'.

A

PSS',

A

A

B

(\sqrt{7}, 0)

(-\sqrt{7}, 0)

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9 x^{2}+16 y^{2}=144

\mathrm{PA}+\mathrm{PB}

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

r

\frac{x^2}{25}+\frac{y^2}{16}=1

P

x=0

Q

R

Q

y=x

Q

R

N P

Q

P

O