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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
Let Tr{T_r} be the rrth term of an AP forr=1,  2,  3r = 1,\;2,\;3,… If for some positive integers m,  n,  we  have  Tm=1n  and  Tn=1m,  then  Tmnm,\;n,\;\mathrm{we\;hav}e\;{T_m} = \frac{1}{n}\mathrm{\;and}\;{T_n} = \frac{1}{m},\;\mathrm{then}\;{T_{mn}} equals
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Correct option: C
1
Option C (1) is correct because, after solving for the first term (a) and common difference (d) of the AP, substituting into the formula for T_{mn} results in 1.

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