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JEE MATHEMATICS MCQ: PAIR OF STRAIGHT LINES

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Application +4 | -1
If the angle between the lines xa+yb=1,xa−yb=1\frac{x}{a}+\frac{y}{b}=1, \frac{x}{a}-\frac{y}{b}=1 has measure α\alpha, then tan⁡α=……\tan \alpha=\ldots \ldots
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Correct option: D
∣2aba2−b2∣\left|\frac{2 a b}{a^2-b^2}\right|
Option D is correct. The angle between two lines is given by tan⁡α=∣m1−m21+m1m2∣\tan \alpha = \left|\frac{m_1 - m_2}{1 + m_1 m_2}\right|. Substituting the slopes of the given lines, we get tan⁡α=∣2aba2−b2∣\tan \alpha = \left|\frac{2 a b}{a^2 - b^2}\right|.

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