JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

A

lies in the second quadrant and

3 \tan A+4=0

, the value of

2 \cot A-5 \cos A+\sin A

View answer and explanation

Correct option: D

\frac{23}{10}

Option D (

\frac{{23}}{{10}}

) is correct because substituting the values of sin A, cos A, and cot A, derived from the given tangent value and quadrant information, into the expression yields

\frac{{23}}{{10}}

More Questions from TRIGONOMETRY RATIOS

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\tan \alpha=\frac{p}{q}

, where

\alpha=6 \beta

and

\alpha

being an acute angle, then

\frac{1}{2}[p \operatorname{cosec} 2 \beta-q \sec 2 \beta]

is equal to The value of

\cos 12^{\circ}+\cos 84^{\circ}+\cos 156^{\circ}+\cos 132^{\circ}

is If the

\triangle A B C

is acute angled at

C

, then The value of the expression

{\sin ^6}\,\,\theta + {\cos ^6}\,\,\theta + 3{\sin ^2}\,\,\theta \,\,{\cos ^2}\,\,\theta

equals

\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=